If a digital circuit's output simplifies via De Morgan's laws from NOT(A AND B) to (NOT A) OR (NOT B), which consequence follows for test vectors?

💡 Explanation

Simplifying with De Morgan's Law means fewer logic gates are needed to realize the same boolean function, therefore requiring fewer test vectors for complete fault coverage, because testing each gate individually becomes unnecessary; rather than requiring exhaustive testing of all combinations, the reduced complexity allows focused test cases.

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