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Which outcome occurs during high-temperature operation of a solid oxide fuel cell with constant fuel flow rate?

A)Increased open-circuit voltage from Nernst equation
B)Reduced ionic conductivity due to grain growth
C)Decreased cell voltage caused by polarization losses
D)Elevated power output from optimized fuel utilization

💡 Explanation

At high temperatures and constant fuel flow, reaction kinetics accelerate at the electrodes because temperature dependence is exponential (Arrhenius equation), increasing activation polarization and concentration polarization, leading to decreased cell voltage. Therefore, decreased cell voltage results, rather than voltage increase, optimized fuel utilization, or improved conductivity which require lower polarization losses.

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