Which outcome occurs when a dielectric material's temperature in high-voltage capacitor exceeds its Curie temperature?

💡 Explanation

When the dielectric temperature exceeds its Curie temperature, thermal energy disrupts the alignment of electric dipoles resulting in depolarisation which causes a drop in permittivity and capacitance, because the material loses its ability to store charge. Therefore, capacitance drops, rather than change in resistance, breakdown voltage or ESR that require separate failure effects.

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