Which outcome occurs when a parallel-plate capacitor is charged beyond its dielectric strength?

💡 Explanation

When voltage across a capacitor exceeds its dielectric strength, dielectric breakdown occurs because the electric field ionizes the dielectric material creating a conductive path, dissipating stored charge. Therefore, stored charge dissipates through dielectric breakdown, rather than capacitance decreasing, resistance decreasing, or resonant frequency shifting, each requiring different failure mechanisms.

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