Which outcome occurs when a parallel-plate capacitor's dielectric material experiences dielectric breakdown?

💡 Explanation

When dielectric breakdown occurs, the strong electric field exceeds the dielectric strength, causing ionization and forming a conductive path through the insulator. This causes the internal resistance to abruptly decrease because of the created conductive path across the plates. Therefore resistance decreases, rather than linear energy changes, capacitance increase or resonant frequency increase, because these require maintained functionality.

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