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← ScienceWhich outcome results when increasing the plate separation in a charged parallel-plate capacitor?
A)Decreased capacitance, increased potential difference✓
B)Increased capacitance, decreased potential energy
C)Decreased electric field, no change
D)Increased energy density, constant charge
💡 Explanation
Increasing plate separation increases voltage because the capacitance (Q=CV) changes proportionally with distance; this is driven by electrostatic repulsion. This capacitance decreases, voltage increases, therefore the electric potential difference increases rather than staying constant or decreasing, due to energy conservation.
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