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Which outcome results when sulfur hexafluoride's (SF6) breakdown threshold is exceeded?

A)Arc formation and dielectric failure
B)Increased thermal conductivity locally
C)Depletion of ozone concentration layers
D)Enhanced vibrational energy distribution

💡 Explanation

When SF6 exceeds its dielectric breakdown, electron avalanche causes arc formation, leading to dielectric failure because electron collision ionizes SF6 molecules. This exceeds insulating capacity thereby causing electrical discharge, rather than ozone depletion or enhanced vibration.

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