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Which thermodynamic limit results when a Carnot engine operates irreversibly?

A)Efficiency always decreases
B)Entropy remains constant
C)Heat input reduces
D)Work output maximizes

💡 Explanation

A Carnot engine undergoing irreversible processes generates entropy because it deviates its ideal operation; therefore, efficiency drops, reducing the reversible heat-work conversion, rather than increased output under ideal equilibrium conditions.

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