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Logic & Puzzles

Why does a resource allocation graph fail to be represented as a bipartite graph when detecting deadlocks?

A)Processes do not request resources
B)Resources aren't released after allocation
C)Processes request all resources simultaneously
D)Cycles exist between processes and resources

💡 Explanation

A resource allocation graph fails to be bipartite if cycles exist because the graph's nodes cannot be divided into two disjoint sets where every edge connects a node in one set to a node in the other; therefore cycles prevent this division, rather than the manner of requesting resources.

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